u^2-170u+169=0

Solution for u^2-170u+169=0 equation:

u^2-170u+169=0

a = 1; b = -170; c = +169;
Δ = b2-4ac
Δ = -1702-4·1·169
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-168}{2*1}=\frac{2}{2}
=1
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+168}{2*1}=\frac{338}{2}
=169
$